SAT Linear Inequalities — Solve, Graph & Interpret Inequalities | SATMath800
SAT Math · Algebra · Area 05

Linear inequalities

Learn to solve, graph, interpret, and combine inequalities — from a single number-line condition to overlapping regions on the coordinate plane.

Negative numbers Sign reversal Coordinate-plane regions Systems of inequalities

The big idea

An equation usually describes an exact value or a line. An inequality describes a set of possible values or a region of possible points.

Equation
One-variable example: \(x=4\)
Two-variable example: \(y=2x+1\)
A precise value or a line.
Inequality
One-variable example: \(x>4\)
Two-variable example: \(y>2x+1\)
A set of values or a region.
SAT mental model: equation → line; inequality → region; system of inequalities → overlap of regions.

1. Read the inequality before solving

Words such as at least, at most, more than, and less than tell you which comparison symbol to use.

WordsSymbolMeaning
at least\(\ge\)greater than or equal to
at most\(\le\)less than or equal to
more than\(>\)strictly greater than
less than\(<\)strictly less than
Boundary matters: \(x\ge4\) includes 4. \(x>4\) does not.

2. One-step inequalities

Solve them like equations — with one critical exception: multiplying or dividing by a negative number reverses the inequality.

Add or subtract the same number

\(x-9=14\)
\(x-9\)\(+9\)\(=14\)\(+9\)
\(x=23\)
\(x-9>14\)
\(x-9\)\(+9\)\(>14\)\(+9\)
\(x>23\)

Multiply or divide by a positive number

\(\frac{x}{4}\le6\)
\(\frac{x}{4}\)\(\times4\)\(\le6\)\(\times4\)
\(x\le24\)

3. The critical rule: a negative reverses the sign

When you multiply or divide both sides of an inequality by a negative number, the order of the numbers reverses.

Number-line reflection
−4−2024 multiply by −1 → reflection
\(-3x<12\)
\(-3x\)\(\div(-3)\)\(>12\)\(\div(-3)\)
\(x>-4\)
Do not memorize only the arrow. Think: multiplying by a negative reverses the number line, so the order reverses too.

4. Negative numbers can make inequalities feel unfamiliar

On a number line, numbers farther to the right are greater. Therefore \(-2>-5\), even though 5 is greater than 2 in absolute value.

\(-5<-2<0<3\)

When checking a solution, compare the actual numbers — not their distances from zero.

5. Multi-step inequalities

Use the same algebraic structure you used for equations. Keep the inequality balanced while isolating the variable.

\(3x-7\le11\)
\(3x-7\)\(+7\)\(\le11\)\(+7\)
\(3x\le18\)
\(3x\)\(\div3\)\(\le18\)\(\div3\)
\(x\le6\)
\(-4x+5>21\)
\(-4x>16\)
\(-4x\)\(\div(-4)\)\(<16\)\(\div(-4)\)
\(x<-4\)

6. Compound inequalities

A compound inequality can describe values between two boundaries.

\(-2\le x<5\)

This means \(x\) is at least \(-2\) but less than 5. The left endpoint is included; the right endpoint is not.

Reading the boundary symbols
−2 included 5 excluded

7. Inequalities from real-world constraints

SAT questions often ask you to turn a practical condition into an inequality before solving it.

Capacity
“No more than 48 students” → \(n\le48\)
Minimum
“At least 750 points” → \(p\ge750\)
Budget
“Cannot spend more than $320” → \(C\le320\)
Distance
“Must be farther than 12 km” → \(d>12\)
Context check: after solving, ask what the variable represents and whether the answer must be an integer, positive, or otherwise restricted.

8. Inequalities in two variables

A linear equation such as \(y=2x-1\) gives a boundary line. The inequality \(y>2x-1\) gives the points above that line.

A line becomes a region
xy y > 2x − 1 solution region

Solid or dashed?

\(y\ge2x-1\)
Use a solid boundary because points on the line are included.
\(y>2x-1\)
Use a dashed boundary because points on the line are excluded.

9. How to decide which side to shade

When the inequality is not already solved for \(y\), or when the graph is unfamiliar, use a test point.

1
Draw the boundary line using the equation obtained by replacing the inequality with \(=\).
2
Choose an easy point that is not on the boundary, often \((0,0)\).
3
Substitute the point into the original inequality.
4
If the inequality is true, shade the side containing the test point. If it is false, shade the other side.
Example: Test \((0,0)\) in \(y>2x-1\): \(0>2*(0)-1\) becomes \(0>-1\), which is true. Therefore the solution region contains \((0,0)\).

10. Which ordered pair satisfies an inequality?

Do not try to judge the graph by appearance alone. Substitute the ordered pair into the inequality.

For \(3x-y\le7\), test \((2,1)\): \(3*(2)-1=5\le7\). So \((2,1)\) is a solution.
Coordinate order matters: \((x,y)\) means substitute the first number for \(x\) and the second for \(y\).

11. Systems of linear inequalities

A system requires all inequalities to be true at the same time. On a graph, that means we first identify each solution region, then keep only the part where the regions overlap.

See the overlap step by step
1. First region y ≥ x + 1 (0, 1) xy shade above the line 2. Second region y ≤ −x + 7 (0, 7) xy shade below the line 3. Keep only the overlap above blue line + below orange line to the left of the intersection (3, 4) overlap = solutions common to both inequalities xy
How to identify the overlap: shade each inequality separately. Then look for points that lie in both regions. Here, those points lie above the blue line and below the orange line, to the left of their intersection, so the green region is the solution region.
Note: The shaded region shown in the graphs is only the portion visible in the graph window. The actual solution region continues indefinitely to the left.
Check a point: a point in the overlap must make both inequalities true. For example, \((3,4)\) satisfies \(4\ge3+1\) and \(4\le-3+7\).

12. Finding the boundary intersection

When two boundary lines meet, their intersection can help describe the corner of the solution region. Solve the two boundary equations as a system.

\(y=x+2\)
\(y=-x+6\)
\(x+2=-x+6\)
\(2x=4\)
\(x=2,\quad y=4\)

The boundary lines meet at \((2,4)\). Whether that point belongs to the final solution depends on whether the original inequalities include their boundaries.

13. Integer constraints can change the final answer

Some SAT contexts describe a count of people, items, days, or other quantities that must be whole numbers.

\(7+3n\ge40\)
\(3n\ge33\)
\(n\ge11\)

Here 11 is already an integer, so it is the smallest possible value. If the algebra produced \(n\ge11.4\) and \(n\) represented a number of students, the smallest possible value would be 12.

14. A reliable SAT inequality strategy

1
Identify the condition. Translate words such as at least, at most, more than, or less than.
2
Solve carefully. Use ordinary algebra, but reverse the inequality when multiplying or dividing by a negative.
3
Represent it. Use a number line for one variable and a boundary line plus a shaded region for two variables.
4
Interpret it. Check units, integer restrictions, and what the variable actually represents.
5
Combine it. For a system, keep only points that satisfy every condition.
Observe → Identify → Decompose → Reason → Solve → Verify

Practice: linear inequalities

These questions are original SATMath800 practice. They use the same kinds of reasoning emphasized in College Board Algebra materials without reproducing source questions.

1. Solve the inequality

What is the solution to \(5x-8\ge27\)?

  • A) \(x\ge5\)
  • B) \(x\ge7\)
  • C) \(x\le7\)
  • D) \(x\le5\)
Solution: \(5x\ge35\), so \(x\ge7\). Answer: B
2. A negative coefficient

Which inequality is equivalent to \(-6x+4<22\)?

  • A) \(x<-3\)
  • B) \(x>3\)
  • C) \(x<- \frac{13}{3}\)
  • D) \(x>\frac{13}{3}\)
Solution: \(-6x<18\). Dividing by \(-6\) reverses the sign: \(x>-3\). Answer: B
3. Negative numbers

Which statement is true?

  • A) \(-8>-3\)
  • B) \(-5<-9\)
  • C) \(-2>-7\)
  • D) \(0<-4\)
Solution: \(-2\) lies to the right of \(-7\), so \(-2>-7\). Answer: C
4. A practical constraint

A school can purchase no more than 36 tablets. If \(t\) represents the number of tablets purchased, which inequality represents the condition?

  • A) \(t<36\)
  • B) \(t\le36\)
  • C) \(t>36\)
  • D) \(t\ge36\)
Solution: “No more than” means at most, so 36 is included. Answer: B
5. Minimum value in context

A machine produces 18 parts each hour. After \(h\) hours, at least 144 parts must have been produced. What is the minimum whole-number value of \(h\)?

  • A) 6
  • B) 7
  • C) 8
  • D) 9
Solution: \(18h\ge144\), so \(h\ge8\). Answer: C
6. Compound inequality

Which value satisfies the compound inequality below?

−4<x≤3
  • A) \(-4\)
  • B) \(-5\)
  • C) \(3\)
  • D) \(4\)
Solution: Values must be greater than \(-4\) and no greater than 3. Answer: C
7. Equivalent inequality

Which inequality is equivalent to \(2-4x\le18\)?

  • A) \(x\le-4\)
  • B) \(x\ge-4\)
  • C) \(x\le-5\)
  • D) \(x\ge-5\)
Solution: \(-4x\le16\). Divide by \(-4\): \(x\ge-4\). Answer: B
8. Ordered pair check

Which ordered pair satisfies \(2x+y<9\)?

  • A) \((4,2)\)
  • B) \((3,4)\)
  • C) \((2,4)\)
  • D) \((5,0)\)
Solution: For \((2,4)\), \(2*(2)+4=8<9\). Answer: C
9. Boundary inclusion

Which boundary should be used when graphing \(y\ge-3x+5\)?

  • A) A dashed line, because the line is excluded
  • B) A solid line, because the line is included
  • C) A dashed line, because the slope is negative
  • D) A solid line, because the slope is negative
Solution: The symbol \(\ge\) includes equality, so the boundary is solid. Answer: B
10. Test a point

Which point lies in the solution region of \(y< x+3\)?

  • A) \((0,4)\)
  • B) \((2,6)\)
  • C) \((1,5)\)
  • D) \((3,5)\)
Solution: Test \((3,5)\): \(5<3+3\), which is true. Answer: D
11. System of inequalities

Which ordered pair satisfies both \(y\ge x-1\) and \(y<5\)?

  • A) \((2,0)\)
  • B) \((4,2)\)
  • C) \((1,1)\)
  • D) \((6,4)\)
Solution: \((1,1)\): \(1\ge0\) and \(1<5\). Both conditions are true. Answer: C
12. A two-variable constraint

A club has \(x\) adult members and \(y\) student members. The club can have no more than 80 members. Which inequality represents this condition?

  • A) \(x+y<80\)
  • B) \(x+y>80\)
  • C) \(x+y\le80\)
  • D) \(x+y\ge80\)
Solution: “No more than 80” means the total may equal 80 but cannot exceed it. Answer: C
13. Integer interpretation

A delivery service charges a fixed fee of $9 plus $4 for each package. A customer has no more than $41 available. If \(p\) is the number of packages, what is the greatest possible whole-number value of \(p\)?

  • A) 7
  • B) 8
  • C) 9
  • D) 10
Solution: \(9+4p\le41\). Thus \(4p\le32\), so \(p\le8\). Answer: B
14. Boundary intersection

The boundaries of a system are \(y=2x+1\) and \(y=-x+7\). At what point do the two boundary lines intersect?

  • A) \((1,3)\)
  • B) \((2,5)\)
  • C) \((3,7)\)
  • D) \((4,9)\)
Solution: Set the equations equal: \(2x+1=-x+7\). Then \(3x=6\), so \(x=2\), and \(y=5\). Answer: B
15. Which side of the boundary?

For \(y\le -2x+4\), which point is in the solution region?

  • A) \((0,5)\)
  • B) \((1,3)\)
  • C) \((2,1)\)
  • D) \((3,-3)\)
Solution: Test \((3,-3)\): \(-3\le-2*(3)+4=-2\), which is true. Answer: D
16. System interpretation

A student must satisfy \(x+y\le12\) and \(x\ge5\). Which point satisfies both conditions?

  • A) \((4,6)\)
  • B) \((5,8)\)
  • C) \((6,6)\)
  • D) \((7,7)\)
Solution: \((6,6)\) gives \(12\le12\) and \(6\ge5\). Answer: C
17. Reverse the sign

Which inequality is equivalent to \(-2x\ge14\)?

  • A) \(x\ge-7\)
  • B) \(x\le-7\)
  • C) \(x\ge7\)
  • D) \(x\le7\)
Solution: Divide by \(-2\) and reverse the sign: \(x\le-7\). Answer: B
18. Model and solve

A fundraiser earns $6 for each item sold and has already collected $48. The goal is to collect at least $150. If \(n\) is the number of additional items sold, what is the minimum whole-number value of \(n\)?

  • A) 16
  • B) 17
  • C) 18
  • D) 19
Solution: \(48+6n\ge150\), so \(6n\ge102\), giving \(n\ge17\). Answer: B

Mastery check

Manipulate
Can you solve an inequality without forgetting the negative-sign reversal?
Represent
Can you choose a solid or dashed boundary and shade the correct region?
Interpret
Can you turn an “at least” or “no more than” condition into correct mathematics?
Combine
Can you identify the overlap of two inequality regions and check a point against every condition?
Learn → Practice → Master → Perform. The goal is not just to solve an inequality. It is to recognize what the inequality means and verify the result.
SATMath800.com
Content prepared by Dr. Aytekin Vargün.
Original SAT Math instruction and practice created for SATMath800.

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