SAT Linear Inequalities in Two Variables | Graphs, Regions & Practice | SATMath800
SAT Math · Algebra · 07

Linear inequalities in two variables

Use boundary lines, test points, intercepts, and shaded regions to represent and interpret solutions in the xy-plane.

Boundary lines Solid vs dashed Shading Test points Intercepts

The big idea

A linear inequality in two variables describes a region of the xy-plane, not usually a single point.

Boundary equation
\(y=2x-3\)

The equation gives the line that separates the two sides.

Linear inequality
\(y>2x-3\)

The inequality selects one side of the boundary line.

SAT mental model: boundary line → decide whether the boundary is included → identify the correct side → verify with a point when useful.

1. Start with the boundary line

Replace the inequality symbol with an equals sign. The resulting equation is the boundary line.

\(y>2x-3\) \(y=2x-3\)

This line divides the plane into two regions. The original inequality tells you which region contains the solutions.

Solid boundary: \(\le\) or \(\ge\) Dashed boundary: \(<\) or \(>\)

2. Solid or dashed?

Solid boundary
\(y\ge2x-3\)

Points on the boundary are included.

Dashed boundary
\(y>2x-3\)

Points on the boundary are excluded.

3. Shade above or below

Once the inequality is written as an inequality in \(y\), the direction of the inequality tells you which side to shade.

Above the boundary
\(y>mx+b\)

Larger \(y\)-values lie above the line.

Below the boundary
\(y<mx+b\)

Smaller \(y\)-values lie below the line.

Example: above the line
y = 2x − 3 y x

The dashed boundary is excluded; the region above it is shaded.

Example: below the line
(0, 4) (4, 0) y = −x + 4 y x

The solid boundary is included; the region below it is shaded.

4. When the inequality is not solved for \(y\)

Rewrite the inequality so that \(y\) is isolated. If you divide by a negative number, reverse the inequality symbol.

\(3x+2y\le12\)
\(2y\le-3x+12\)
\(y\le-\frac{3}{2}x+6\)
The boundary is solid because equality is included, and the solution region is below the boundary.

5. Use a test point when the shading is not obvious

Pick a point that is not on the boundary, substitute its coordinates into the inequality, and use the result to identify the correct side.

\(y>x-4\)
\(\text{Test }(0,0):\quad 0>0-4\)
\(0>-4\quad\text{is true}\)

Therefore the region containing \((0,0)\) is the solution region.

6. Ordered pairs can be tested directly

A point \((a,b)\) is a solution exactly when its coordinates make the original inequality true.

\(b=ma+c\)

Use the original inequality symbol in place of the square. Do not test only the boundary equation when the question asks whether a point is a solution.

7. Read intercepts from the boundary

An x-intercept is where the boundary crosses the x-axis, so its y-coordinate is 0. A y-intercept is where the boundary crosses the y-axis, so its x-coordinate is 0.

Example: intercepts are shown
(0, 3) (6, 0) y = −½x + 3 y x

The y-intercept is where the line crosses the y-axis. The x-intercept is where the line crosses the x-axis.

8. Read a graph backwards

SAT questions may give you the graph first and ask you to determine the inequality. Use four pieces of evidence:

1
Boundary: identify the equation of the line.
2
Boundary type: solid means equality is included; dashed means it is excluded.
3
Shading: determine which side contains the shaded points.
4
Verify: choose a visible point and substitute it.

9. Context can create a region

If two variables represent quantities, a linear inequality can describe a constraint on all possible pairs.

\(2x+3y\le18\)

Here every nonnegative ordered pair \((x,y)\) satisfying the inequality is a possible combination under the stated constraint. The graph therefore represents many possible combinations rather than one answer.

10. Integer and nonnegative restrictions matter

The algebraic region may contain infinitely many real-number points, but a context can restrict which points are meaningful.

Nonnegative quantity
\(x\ge0\)

Useful for counts, lengths, amounts, and other quantities that cannot be negative.

Whole-number quantity
\(x\in\{0,1,2,3,\ldots\}\)

Useful when a variable counts people, objects, days, or other discrete items.

11. A reliable SAT strategy

1
Find the boundary. Replace the inequality with equality.
2
Decide inclusion. Use a solid or dashed boundary.
3
Identify the region. Use above/below or test a point.
4
Read the graph. Use the axes and labeled intercepts when the question asks for them.
5
Verify. Substitute a candidate point into the original inequality.
Observe → Identify → Decompose → Reason → Solve → Verify

Visual practice

These questions require you to read the coordinate plane. Every graph provides the equation or the axis information needed for the task.

Visual practice 1

The graph shows the boundary line \(y=x-2\) as a solid line, with the region above the line shaded. Which inequality represents the shaded region?

(0, −2) (2, 0) y = x − 2 y x
  • A) \(y>x-2\)
  • B) \(y\ge x-2\)
  • C) \(y<x-2\)
  • D) \(y\le x-2\)
Solution: The region is above the line and the boundary is solid, so the inequality is \(y\ge x-2\).
Visual practice 2

The graph shows the dashed boundary \(y=-\frac12x+3\). What is the x-intercept of the boundary line?

(0, 3) (6, 0) y = −½x + 3 y x
  • A) \((0,3)\)
  • B) \((3,0)\)
  • C) \((6,0)\)
  • D) \((0,6)\)
Solution: The x-intercept occurs where \(y=0\), and the graph labels that point as \((6,0)\).
Visual practice 3

The graph shows the boundary \(y=-x+4\) and point \(P=(2,1)\). Is \(P\) a solution of \(y<-x+4\)?

P = (2, 1) y = −x + 4 y x
  • A) Yes
  • B) No
  • C) Only if the boundary is solid
  • D) Only when \(x<0\)
Solution: At \((2,1)\), \(1<-2+4=2\), so the point is in the solution region.
Visual practice 4

The graph shows the two boundary lines \(y=x+1\) and \(y=-x+7\). At what point do the boundary lines intersect?

(3, 4) y = x + 1 y = −x + 7 y x
  • A) \((2,3)\)
  • B) \((3,4)\)
  • C) \((4,3)\)
  • D) \((3,5)\)
Solution: Set the boundary equations equal: \(x+1=-x+7\). Thus \(x=3\) and \(y=4\).

Additional practice

Original SATMath800 practice. The set mixes algebraic, graphical, contextual, and ordered-pair reasoning rather than repeating one question pattern.

Question 1

Which point is a solution to \(y>2x-3\)?

  • A) \((0,-4)\)
  • B) \((1,0)\)
  • C) \((2,0)\)
  • D) \((-1,-6)\)
Solution: For \((1,0)\), \(0>2(1)-3=-1\), so the point satisfies the inequality.
Question 2

Which inequality represents the region above \(y=-3x+5\), including the boundary?

  • A) \(y<-3x+5\)
  • B) \(y\le-3x+5\)
  • C) \(y>-3x+5\)
  • D) \(y\ge-3x+5\)
Solution: Above gives a greater-than relationship, and including the boundary requires equality to be allowed: \(y\ge-3x+5\).
Question 3

Which statement about \(y<\frac12x+4\) is true?

  • A) The boundary is solid and the region is above it.
  • B) The boundary is dashed and the region is above it.
  • C) The boundary is dashed and the region is below it.
  • D) The boundary is solid and the region is below it.
Solution: The strict symbol makes the boundary dashed, and smaller \(y\)-values are below the line.
Question 4

Which inequality is equivalent to \(3x+2y\le12\)?

  • A) \(y\le-\frac32x+6\)
  • B) \(y\ge-\frac32x+6\)
  • C) \(y\le\frac32x+6\)
  • D) \(y\ge\frac32x-6\)
Solution: Subtract \(3x\) and divide by positive 2, giving \(y\le-\frac32x+6\).
Question 5

A point \((a,b)\) lies on the boundary of \(2x-y>7\). Which equation must be true?

  • A) \(2a-b>7\)
  • B) \(2a-b=7\)
  • C) \(2a-b<7\)
  • D) \(a-2b=7\)
Solution: Boundary points satisfy the boundary equation, so \(2a-b=7\).
Question 6

The inequality \(x-2y\ge6\) is graphed in the xy-plane. Which point is in its solution region?

  • A) \((8,1)\)
  • B) \((4,0)\)
  • C) \((1,-2)\)
  • D) \((-1,-2)\)
Solution: For \((8,1)\), \(8-2(1)=6\), so the point satisfies the inclusive inequality.
Question 7

A line has equation \(4x+y=8\). Which inequality represents the half-plane below this line?

  • A) \(4x+y<8\)
  • B) \(4x+y>8\)
  • C) \(4x+y\le-8\)
  • D) \(4x+y\ge8\)
Solution: Rewrite as \(y=-4x+8\). Below the line means \(y<-4x+8\), so \(4x+y<8\).
Question 8

Which point lies on the boundary line of \(5x+2y\le20\)?

  • A) \((0,8)\)
  • B) \((2,5)\)
  • C) \((4,0)\)
  • D) \((6,-5)\)
Solution: The boundary is \(5x+2y=20\). For \((4,0)\), \(5(4)+2(0)=20\).
Question 9

A study plan allows at most 420 minutes. If \(x\) is the number of minutes spent on algebra and \(y\) is the number of minutes spent on geometry, which inequality represents the time constraint?

  • A) \(x+y\le420\)
  • B) \(xy\le420\)
  • C) \(x+y\ge420\)
  • D) \(xy\ge420\)
Solution: The total time is \(x+y\) minutes. “At most 420” means the total cannot exceed 420, so \(x+y\le420\).
Question 10

For \(y\ge-2x+1\), which description is correct?

  • A) Dashed boundary; shade below.
  • B) Dashed boundary; shade above.
  • C) Solid boundary; shade below.
  • D) Solid boundary; shade above.
Solution: The inclusive symbol makes the boundary solid, and greater \(y\)-values are above the line.
Question 11

Which point satisfies both \(y\le x+2\) and \(y>-x+4\)?

  • A) \((0,1)\)
  • B) \((1,3)\)
  • C) \((2,3)\)
  • D) \((4,0)\)
Solution: At \((2,3)\), both conditions hold: \(3\le4\) and \(3>2\).
Question 12

A constraint is written as \(2x+5y\ge30\). Which statement about its boundary is correct?

  • A) The boundary is \(2x+5y>30\).
  • B) The boundary is \(2x+5y=30\).
  • C) The boundary is \(2x+5y<30\).
  • D) There is no boundary line.
Solution: Replace the inequality symbol with equality to obtain the boundary equation.
Question 13

The graph of a linear inequality has a dashed boundary line. Which inequality symbol could describe it?

  • A) \(\le\)
  • B) \(\ge\)
  • C) \(<\)
  • D) Either \(\le\) or \(\ge\)
Solution: A dashed boundary represents a strict inequality. Among the choices, only \(<\) is strict.
Question 14

Which inequality describes the half-plane containing \((0,0)\) for the line \(y=3x-5\), with the boundary included?

  • A) \(y\ge3x-5\)
  • B) \(y\le3x-5\)
  • C) \(y>3x-5\)
  • D) \(y<3x-5\)
Solution: At the origin, \(0\ge-5\) is true, so the included region is \(y\ge3x-5\).
Question 15

A water tank must hold at least 600 liters. If \(x\) and \(y\) are nonnegative quantities and the total is \(x+y\), which inequality models the requirement?

  • A) \(x+y<600\)
  • B) \(x+y\le600\)
  • C) \(x+y>600\)
  • D) \(x+y\ge600\)
Solution: At least includes equality and requires a value no smaller than 600.
Question 16

Which point satisfies \(6x-3y<0\)?

  • A) \((1,1)\)
  • B) \((0,1)\)
  • C) \((2,4)\)
  • D) \((3,1)\)
Solution: For \((0,1)\), \(6(0)-3(1)=-3<0\).
SATMath800.com · Content prepared by Dr. Aytekin Vargün · Original SAT Math instruction and practice created for SATMath800.

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